las metematicas y nuestro entorno: formulas de derivadas

En las fórmulas siguientes se considera que $x,a,b,k \in \mathbb{R}, n \in \mathbb{N}$ :

$f\left(x\right) = a$	$f'\left(x\right) = 0$
$f\left(x\right) = x$	$f'\left(x\right) = 1$
$f\left(x\right) = ax$	$f'\left(x\right) = a$
$f\left(x\right) = ax + b$	$f'\left(x\right) = a$
$f\left(x\right) = x^n$	$f'\left(x\right) = nx^{n-1}$
$f\left(x\right) = \sqrt{x}$	$f'\left(x\right) = \frac{1}{2\sqrt{x}}$
$f\left(x\right) = e^x$	$f'\left(x\right) = e^x$
$f\left(x\right) = \ln(x)$	$f'\left(x\right) = \frac{1}{x}$
$f\left(x\right) = a^x (a >0)$	$f'\left(x\right) = a^x \ln(a)$
$f\left(x\right) = \log_{b}(x)$	$f'\left(x\right) = \frac{1}{x\ln(b)}$
$f\left(x\right) = \frac{1}{x^n} = x^{-n}$	$f'\left(x\right) = -nx^{-n-1} = \frac{-n}{x^{n+1}}$
$f\left(x\right) = \operatorname{sen}(x)$	$f'\left(x\right) = \cos(x)$
$f\left(x\right) = \cos(x)$	$f'\left(x\right) = -\operatorname{sen}(x)$
$f\left(x\right) = \tan(x)$	$f'\left(x\right)=\sec^2(x)=\frac{1}{cos^2(x)}=1+\tan^2(x)$
$f\left(x\right) = \csc(x)$	$f'\left(x\right) = -\csc(x)\cot(x)$
$f\left(x\right) = \sec(x)$	$f'\left(x\right) = \sec(x)\tan(x)$
$f\left(x\right) = \cot(x)$	$f'\left(x\right) = -\csc^2(x)$
$f\left(x\right) = \operatorname{arcsen}(x)$	$f'\left(x\right) = \frac{1}{\sqrt{1-x^2}}$
$f\left(x\right) = \arccos(x)$	$f'\left(x\right) = \frac{-1}{\sqrt{1-x^2}}$
$f\left(x\right) = \arctan(x)$	$f'\left(x\right) = \frac{1}{1+x^2}$
$f\left(x\right) = g(x) \pm h(x)$	$f'\left(x\right) = g'(x) \pm h'(x)$
$f\left(x\right) = g(x) \cdot h(x)$	$f'\left(x\right) = g'(x) \cdot h(x) + g(x) \cdot h'(x)$
$f\left(x\right) = k \cdot g(x)$	$f'\left(x\right) = k \cdot g'(x)$
$f\left(x\right) = \frac{g(x)}{h(x)}$	$f'\left(x\right) = \frac{g'(x) \cdot h(x) - g(x) \cdot h'(x)}{h^2(x)}$
$f\left(x\right) = g\left(x\right)^{h\left(x\right)}$	$f'\left(x\right) = h\left(x\right) \cdot g'\left(x\right) \cdot g\left(x\right)^{\left(h\left(x\right)-1\right)} + g\left(x\right)^{h\left(x\right)} \cdot h'\left(x\right) \cdot ln\left(g\left(x\right)\right)$
$f\left(x\right) = g \circ h = g(h(x))$	$f'\left(x\right) = (g'\circ h) \cdot h' = g'(h(x)) \cdot h'(x)$

las metematicas y nuestro entorno

viernes, 2 de diciembre de 2011

formulas de derivadas

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